LARGE_INTEGER litmp; 

       LONGLONG QPart1,QPart2;

       double dfMinus, dfFreq, dfTim; 

       QueryPerformanceFrequency(&litmp);

       dfFreq = (double)litmp.QuadPart;// 获得计数器的时钟频率

       QueryPerformanceCounter(&litmp);

       QPart1 = litmp.QuadPart;// 获得初始值

       do

       {

          QueryPerformanceCounter(&litmp);

          QPart2 = litmp.QuadPart;//获得中止值

          dfMinus = (double)(QPart2-QPart1);

          dfTim = dfMinus / dfFreq;// 获得对应的时间值，单位为秒

       }while(dfTim<0.000001);